The so­lu­tion:

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Re­fer Fig­ure 1. Let M be the man and T be the tem­ple on the op­po­site bank of the river. The man wants to reach T but the river is flow­ing at a speed of 3m/s. Due to the flow of the river, the man reaches point P (i.e., he drifts slightly off-course). Now the time taken by the man to cross the river can be cal­cu­lated by con­sid­er­ing the direc­tion MT only (us­ing vec­tors) = MT/ 4 = 800/4 =200 sec .... (1) In 200 sec, the man drifts to point P, so the dis­tance PT = 3 * 200 = 600 m .... (2) Now the man walks at a speed of 2 m/s, so the time taken by him to travel from P to T = PT/ 2 = 600/2= 300 sec .... (3) So the to­tal time re­quired to reach T = eqn 1 + eqn 3 = 200 + 300 = 500 sec­onds.

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