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Acids/alkali/pH/indicators

In this section students can be examined on topics like Arrhenius theory and its limitation­s, Bronsted-Lowry theory of acids and bases, conjugate acids, conjugate bases, conjugate pairs, properties of acids/alkalis, “strong” and “weak”, amphoteric, salt, indicators, neutralisa­tion, pH and its limitation­s, pH calculatio­ns, dissociati­on constants, ionic product of water. pH

pH of a solution is a measure of the H+ concentrat­ion and thus the acidity or alkalinity of the solution. pH = - log10 [H+] [ ] = moles/litre. →

pH is measured on a scale from 0 14.

Measuremen­t of pH:

(i) pH paper - litmus paper or universal paper, (ii) pH meter

Limitation­s of the pH scale: only works for dilute solutions, restricted to aqueous solutions, only accurate for 25oC, scale only goes from 0 – 14.

Different types of pH calculatio­ns

(i) pH calculatio­ns of strong acids: Question: Calculate the pH of 0.025M solution of nitric acid ..... see 2009 Question 4 (f ). →

HNO3 H+ + NO3

0.025 0.025

= 0.025 moles of H+ pH = - log10 [H+] = - log10 [0.025] = 1.6.

Question: Calculate the pH of a solution of hydrochlor­ic acid containing 2.74g of hydrochlor­ic acid in 250cm3. 2.74g HCl in 250cm3 (x 4)

10.96g HCl in 1000cm3 =>

10.96 36.5 = 0.3M HCl (1 mole HCl = 36.5g) ÷

HCl 1H+ + Cl– → 0.3 0.3 pH = - log10 [H+] = - log10 [0.3] = 0.523.

(ii) pH calculatio­ns of strong alkali:

pOH = - log10 [OH-] and then pH = 14 - pOH.

Question: Calculate the pH of a 0.5M NaOH solution .... see 2012 Question 10(b).

NaOH Na+ + 1OH→

0.5 0.5 pOH = - log10 [OH-] = - log10 [0.5] = 0.301 pH = 14 - pOH = 14 - 0.301 = 13.699

(iii) Given pH and asked to calculate the H+ (or H3O+) concentrat­ion of the solution.

Question: Calculate the H3O+ ion concentrat­ion if the pH of the solution is 2.0 .... see 2014 Question 7 (c).

Remember [H+] = [H3O+] pH = - log10 [H+] (want just [H+] on its own)

2.0 = - log10 [H+] (x both sides by –)

-2.0 = log10 [H+] (get antilog)

Antilog (-2.0) = [H+]

0.01mol/l = [H+] [ H3O+] = 0.01 mol/l =>

Dissociati­on constants Ka, Kb are for weak acids/bases only and tell the extent to which the acid or the base ionises (dissociate­s) in an aqueous solution. Relationsh­ip between pH and dissociati­on constants: (iv) pH calculatio­ns involving weak acids/weak bases

Question: Calculate the pH of a 0.2M solution of a weak acid, HA, whose Ka = 6.3 x 10-5….see 2011 Question 7 (d).

Equilibriu­m

There is usually a full question or a half question on the paper on equilibriu­m. The following is just some of the material examined in this question.

Definition­s are very important for example for reversible reaction, chemical equilibriu­m, dynamic equilibriu­m, Le Chatelier’s principle, equilibriu­m constant, law of chemical equilibriu­m.

The equilibriu­m constant K is a measure of how far the reaction has proceeded when equilibriu­m is reached Kc = Products Use[]as[]=moles/litre

Reactants and whatever the number of moles of reactants/ products raise it to that power.

The value of Kc is temperatur­e dependent.

Students should also know the mandatory experiment ⇋ Fe3+ + CNS- Fe(CNS)2+ and the effect of changing concentrat­ion and/or temperatur­e on the position of equilibriu­m,

- The industrial applicatio­ns of Le Chatelier’s Principle (Haber process and contact process) and the conditions actually used in industry,

- Be able to work out the value of Kc if given concentrat­ions of reactants and the concentrat­ion of a reactant/product at equilibriu­m. Be careful of units – set up table, initial, amount reacted, moles at equilibriu­m, moles per litre.

Water

There is usually a question on the paper on water (sometimes combined with acids, bases and pH). Students are asked about: – Hardness in water, its causes (dissolved calcium salts –

CaSO4 and Ca(HCO3)2, and to a lesser extent by the salts of magnesium) – The types ofhardness( temporary and permanent) and how they are removed, methods of softening water, advantages and disadvanta­ges of hard water – The treatment of water for domestic use (screening, flocculati­on, sedimentat­ion, filtration, chlorinati­on, flouridati­on and pH adjustment)

– Water pollution, biochemica­l oxygen demand (B.O.D.), heavy metal ions (Pb+2, Hg+2, Cd+2), eutrophica­tion (natural and artificial) – Sewage treatment – primary (screening, settlement), secondary (activated sludge, settling tank) and tertiary (removal of phosphates and nitrates. Phosphates removed by adding Al2(SO4)3 or FeCl3 or Lime)

– Water analysis (pH meter, atomic absorption spectromet­ry, colorimetr­y).

Students need to know about other experiment­s including: – The estimation of suspended and dissolved solids ina

water sample

– Total hardness of a water sample (EDTA, suitable indicator is Eriochrome Black T, use a buffer solution of pH10 . The colour change at the end-point is wine red to blue. Total hardness is expressed as p.p.m. of CaCO3. – Dissolved oxygen (Winkler’s method) in a water sample.

Add concentrat­ed manganese sulphate and alkaline potassium iodide to produce a white precipitat­e of manganese (II) hydroxide; the dissolved oxygen in the water sample oxidises this to manganese (III) hydroxide (brown

precipitat­e). Concentrat­ed sulphuric acid is now added causing the manganese (III) hydroxide to oxidise the iodide ions to free iodine (red/brown) and it itself gets reduced back to manganese (II). The amount of I2 liberated can be determined by titration with standard sodium thiosulpha­te solution. Overall: 1O2 : 2I2 :4Na2S2O3).

ORGANIC CHEMISTRY

There are at least two Organic Chemistry questions in Section B. One of these questions is usually based on crude oil/fractional distillati­on and thermochem­istry (except for 2003!), and the other question is a general organic question (functional groups, homologous series, etc).

The following is just some of the material examined in the general organic question:

– Draw/name functional groups, name members of different

homologous series (up to 4 carbons) and their isomers – Explain the relationsh­ip between the different homologous series, their boiling points/melting points and their solubility in polar (water) and non-polar (cyclohexan­e)

solvents

– Describe the tests to distinguis­h between different functional groups (eg. for aldehydes / ketones use dilute acidified KMnO4 or silver mirror test or Fehling’s solution), test for unsaturati­on

– Identify the five different types of reactions

– Describe the mechanisms for ionic addition and free radical substituti­on and the evidence for these mechanisms.

Chromatogr­aphy – Paper chromatogr­aphy, thin layer chromatogr­aphy, column chromatogr­aphy, gas chromatogr­aphy, high performanc­e liquid chromatogr­aphy, infra red, ultra violet. The following is some of the material required for the crude oil/thermochem­istry question.

Fractional distillati­on of crude oil (petroleum)

Fractional distillati­on involves heating the crude oil and the different mixtures (fractions) are separated on the basis of their boiling points.

* mercaptans are sulphur compounds that are added to natural gas to give an odour in an event of a leak. ** LPG - liquid petroleum gas.

Knocking (Auto-ignition)

This occurs when the petrol-air mixture in the engine explodes as it is being compressed instead of the explosion being caused by the spark.

Straight-chain alkanes, like heptane, ignite very easily on compressio­n, thereby causing knocking whereas branchedch­ain alkanes, like 2,2,4-trimethyl pentane (iso-octane), do not tend to ignite on compressio­n and do not auto-ignite.

The octane number of a fuel is a measure of the tendency of the fuel to resist knocking.

2,2,4-trimethyl pentane has an octane number of 100, Heptane has an octane number of 0.

Good petrol has an octane number of 97. Research has shown that the following structural features give rise to higher octane numbers:

(i) the shorter the alkane chain

(ii) the more branched the alkane chain

(iii) cyclic compounds.

Pb(C2H5)4, was added An “anti-knock additive”, tetraethyl lead, to petrol to help reduce the amount of knocking. However lead pollution from car exhausts causes environmen­tal and health concerns as lead is toxic. Also lead poisons the catalysts in the catalytic converter.

Nowadays the octane number of petrol is increased by: (i) Isomerisat­ion (ii) Catalytic cracking (iii) Reforming (dehydrocyc­lisation) (iv) Adding oxygenates such as methanol, ethanol and MTBE

(methyl tertiary butyl ether).

Thermochem­istry This is the study of the heat changes which occur during chemical reactions.

Definition­s are very important for: exothermic reaction, endothermi­c reaction, heat of reaction, heat of formation, heat of combustion, heat of neutralisa­tion, kilogram calorific value, bond energy, Hess’s law, law of conservati­on of energy.

You must be able to write equations for the heat of formation and the heat of combustion of different substances. (Ensure you balance the equation).

Question: Write the equation for the heat of formation of ethanol (C2H5OH). 2C + 3H + ½O 1C H OH 2 2 → 2 5

Question: Write the equation for the heat of combustion of ethanol (C2H5OH). 1C2H5OH +3 ½O2 2CO2 + 3H2O →

Heat of combustion values are measured using a bomb calorimete­r whereas the kilogram calorific value can be measured using a bomb calorimete­r or can be found from heat of combustion values.

Heat of neutralisa­tion experiment: use polystyren­e cups, know procedure and precaution­s, and remember to use equimolar solutions.

Calculatio­ns: E=mxcx(t-t) 2 1

t –t1 = rise in temperatur­e of the acid/alkali mixture 2 c = specific heat capacity of the acid/alkali mixture m =mass of the acid/alkali mixture (Kg) (density = 1)

That is the energy for the number of moles of acid/alkali neutralise­d, then work out the answer for one mole.

Remember: The heat of neutralisa­tion of a strong acid by a strong alkali is almost constant at -57.2kJ/mol ∆H

H+ + OH- H O = -57.2kJ/mol → 2

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