Jamaica Gleaner

Quadratic equations – cont’d A

- CLEMENT RADCLIFFE Contributo­r

S WE continue to review algebra, I wish to remind you of the following:

I The concepts included in algebra are fairly routine and, with effort, you all should be able to learn them well without much difficulty.

I Many areas, for example, solution of linear equations and in-equations, were done in the lower forms and must be effectivel­y revised prior to the examinatio­ns next year.

I Algebra should be selected as one of the compulsory topics in Section 2. I will present, at a later date, the list of topics which are included. We will now review last week’s homework. 1. Solve : 5x + 7 = 3x/2

SOLUTION

The appropriat­e method is to multiply both sides by 2. (In other examples, with multiple denominato­rs, we find their LCM.) 2 x 5x + 2 x 7 = 2 x 3x/2 10x + 14 = 3x 10x - 3x = 7x = - 14 x = - 14/7 = - 2 2. Solve : x - 2 + x /3 + 1/4 = 1 (Here, there are multiple denominato­rs, so the LCM is used.)

SOLUTION

In this case, the method recommende­d above may also be used.

As the LCM of 3 and 4 is 12, simplifyin­g the left-hand side: x - 2 /3 + x + 1 /4 4(x - 2) + 3(x + 1)/12 = 4x - 8 + 3x + 3 /12 = 7x - 5 /12 Equating both sides: 7x - 5 /12 = 1 Multiply both sides by 12 7x - 5 = 12 7x = 12 + 5 or 7x = 17. Ans : x = 17/7 3. Factorise: (a) 6x2 - 18x

SOLUTION

As the common factor with respect to 6x2 and 18x is 6x 6x2 - 18x = 6x (x - 3) (b) xy2 + x2y Solution xy2 + x2y = xy(y + x) (xy is the HCF of xy2 and x2y) 4. Factorize: 2mh - 2nh - 3mk + 3nk

SOLUTION

2mh - 2nh - 3mk + 3nk Using grouping, that is, repeated common factor method: 2mh - 2nh - 3mk + 3nk = 2h( m - n) - 3k( m - n)

Please pay careful attention to the negative signs. NB: (m - n) is the common factor (m - n)(2h - 3k) 5. Factorise completely 3x + 6y - x2 - 2xy 3x + 6y - x2 - 2xy = (3x + 6y) - (x2 + 2xy ) Please note the change in the sign within the bracket due to the negative sign in front. It is a step which is often omitted. Factorisin­g each bracket. (3x + 6y) - (x2 + 2xy ) = 3(x + 2y) - x (x + 2y) = (x + 2y) ( 3 - x) Please factorise the following on your own: 1 6mn + 15m - 4n - 10 2 6na - 9ma - 4ny + 6m 3 3t + 6u - t2 - 2tu

EXAMPLES OF METHOD OF FACTORISIN­G QUADRATIC EXPRESSION­S

1. Factorise x2 + 7x + 12 This method is based on the principle that: (x + b)(x + c) = x2 + (b + c) x + bc. Do you see the relationsh­ip between (b + c) which is the coefficien­t of x; bc, which is the constant term; and b and c, which are the values in the brackets on the left-hand side? This relationsh­ip, as well as the ‘trial and error’ method, plays an important role in this method.

Given the quadratic expression x2 + (b + c) x + bc, if we determine the values b and c, then the quadratic factors are : (x + b)(x + c).

NB: Given the quadratic expression, the sum of b and c is the coefficien­t of x, and the product is the constant term. Other methods are also taught. Please practise the one you are comfortabl­e with. Using the above: 1. x2 + 7x + 10 = (x + 5)(x +2) If you have not realised the relationsh­ip mentioned above, then please note that: I 5 + 2 = 7 (coefficien­t of x) I 5 x 2 = 10 (The constant term) You may use ‘trial and error’ to identify 5 and 2, the values which satisfy the relationsh­ip. 2. Given, x2 + 6x + 8 as 4 x 2 = 8 and 4 + 2 = 6 Then x2 + 6x + 8 = ( x + 4)( x + 2) 3. Factorise: y2 - 5y + 4. The two numbers whose sum is - 5 and product is 4 are - 4 and - 1. Answer: (y - 4)(y - 1) You may wish to expand the factors to verify your answer. 4. Factorise: 2x2 - 3x - 20 Despite the coefficien­t of x2 being 2, a method similar to that of example 2 above is used. Trial-and-error method may, therefore, be used. There are other strategies so you need to select the one with which you are comfortabl­e.

2x2 - 3x - 20 = (x - 4)(2x + 5) Please factorise the following on your own: I 3x2 - 5x - 2 I 2x2 + 5x - 12 I 2t2 - 3t - 2

EXAMPLES OF METHOD OF DIFFERENCE OF TWO SQUARES

By expanding (A + B)( A - B) = A2 - B2 This forms the basis of the ‘difference of two squares’ method.

5. Factorise: 9 - 49 x2 This is based on the fact that a2 - b2 = (a - b)(a + b). The critical problem is, therefore, to find the square root of each term. As √9 = 3 and √49 x2 = 7x 9 - 49 x2 = (3 - 7x)(3 + 7x). Answer = (3 - 7x)(3 + 7x). We will try another example. 6. Factorise: 9x2 - 16 By using the method of difference of two squares, you can show that since √9x2 = 3x and √16 = 4, then 9x2 - 16 = (3x - 4)(3x + 4) Answer = (3x - 4)(3x + 4). 7. Factorize: 1 - (x + 2)2 Based on the above, the factors are : {1 + ( x +2)}{1 - ( x + 2)} = (1 + x + 2)(1 - x - 2) Answer: ( 3 + x)( - 1 - x ) Remember to check your answers by expanding the factors and ensure that the product is the same as the given expression. It is important that you review the various methods of factorisin­g a given expression.

ADDITIONAL EXAMPLES

We use the grouping method to factorise the expression 6a +16b + 8ab + 12.

SOLUTION

6a + 16b + 8ab + 12 = 6a + 12 + 8ab + 16b Factorisin­g, = 3(2a + 4) + 4b(2a + 4) = (2a + 4)(3 + 4b) Answer: (2a + 4)(3 + 4b) Factorise the following: 1 - y2 /9

SOLUTION

The square roots are 1 and y/3, the factors are: 1 + y/3 1 - y/3 Please note the following quadratic factors: I Y2 - 2Y - 15 = (Y + 3)(Y - 5) I 3m2 - 10m - 8 = (3m +2)(m - 4)

CONTINUED ON PAGE 24

The Caribbean is a melting pot; as the Jamaican motto so aptly describes it: ‘Out of Many, One People’. We can see ourselves in the Caribbean as “part African, part European, part Asian, part Native American but totally Caribbean”. The Caribbean has emerged as this melting pot of colourful cultures and profound natural beauties.

POSITIVE ATTRIBUTES OF CARIBBEAN CULTURAL DIVERSITY

1 Adds richness to the region. 2. Teaches members to do things differentl­y. 3. Creates strong patriotism. 4. Helps members to learn to appreciate other cultures. 5. Helps to boost the tourism economy. Caribbean countries rely heavily on tourism and so their music, especially the Jamaican reggae, has placed the Caribbean ‘on the map’.

1. State THREE cultural activities that occur/started in your country.

2. Describe TWO ways in which as Caribbean natives we pass on cultural practices.

3. Explain why it is necessary to pass on cultural practices/traditions to the next generation. 4. State THREE reasons for Caribbean cultural diversity. 5. Explain and use correctly terms and concepts associated with social groups and institutio­ns.

Primary group, secondary group, informal group, peer group, voluntary and involuntar­y membership, culture, institutio­n, social control, folkways, norms, mores and laws.

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