Game 7: Celtics, Bucks play for spot against the Sixers

Al Horford has played in four Game 7s. Jason Terry has been in three, his teams winning them all. For them, this is old hat. For just about everyone else who’s had any role in this Boston-Milwaukee series, however, this is new or relatively new territory. The ultimate game awaits the Bucks and Celtics on Saturday night, when their Eastern Conference first-round series ends on Boston’s home floor — the winner moving into the second round to face the Philadelphia 76ers, the loser going home for the summer.

“We’re going to be in a tough position,” Milwaukee guard Eric Bledsoe said. “We’ve just got to come out and fight . ... We’ve just got to find a way.”

The Celtics have been in more Game 7s than any franchise in NBA history. This will be the 32nd such game for Boston, which has gone 22-9 in its previous ones. Milwaukee is going to Game 7 for the 10th time; the Bucks’ franchise is 2-7 so far in those.

“Super exciting,” said Bucks guard Malcolm Brogdon, when asked about how he feels about making it to what will be his first Game 7. “This is what you prepare for the whole season, training camp, the offseason, it all builds up to this. We’ve got to come out and play with energy and not get out of character.”

The Celtics won a Game 7 last season against Washington in the second round, albeit with quite a different roster. There’s four members of the current Boston rotation — Horford,